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131403020283049 is a prime number
BaseRepresentation
bin11101111000001010100110…
…010110001010110010101001
3122020021000011102012100200211
4131320022212112022302221
5114210401341143024144
61143245414131501121
736451361224302454
oct3570124626126251
9566230142170624
10131403020283049
1138961787309909
12128a29517577a1
135842336b25798
142463d2397049b
15102d162957034
hex7782a658aca9

131403020283049 has 2 divisors, whose sum is σ = 131403020283050. Its totient is φ = 131403020283048.

The previous prime is 131403020283013. The next prime is 131403020283053. The reversal of 131403020283049 is 940382020304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131031359353449 + 371660929600 = 11446893^2 + 609640^2 .

It is an emirp because it is prime and its reverse (940382020304131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131403020283049 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403020283149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701510141524 + 65701510141525.

It is an arithmetic number, because the mean of its divisors is an integer number (65701510141525).

Almost surely, 2131403020283049 is an apocalyptic number.

It is an amenable number.

131403020283049 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403020283049 is an equidigital number, since it uses as much as digits as its factorization.

131403020283049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 40.

The spelling of 131403020283049 in words is "one hundred thirty-one trillion, four hundred three billion, twenty million, two hundred eighty-three thousand, forty-nine".