131403032283041 has 2 divisors, whose sum is σ = 131403032283042. Its totient is φ = 131403032283040.

The previous prime is 131403032282999. The next prime is 131403032283067. The reversal of 131403032283041 is 140382230304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131067236371600 + 335795911441 = 11448460^2 + 579479^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403032283041 - 2⁴⁶ = 61034288105377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131403032282992 and 131403032283010.

It is not a weakly prime, because it can be changed into another prime (131403032288041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701516141520 + 65701516141521.

It is an arithmetic number, because the mean of its divisors is an integer number (65701516141521).

Almost surely, 2^{131403032283041} is an apocalyptic number.

It is an amenable number.

131403032283041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403032283041 is an equidigital number, since it uses as much as digits as its factorization.

131403032283041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 131403032283041 its reverse (140382230304131), we get a palindrome (271785262587172).

The spelling of 131403032283041 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-two million, two hundred eighty-three thousand, forty-one".