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131403033021241 is a prime number
BaseRepresentation
bin11101111000001010100111…
…000110110000101100111001
3122020021000012022011112012201
4131320022213012300230321
5114210401402423134431
61143245415304510201
736451361440465162
oct3570124706605471
9566230168145181
10131403033021241
113896179351a243
12128a2955a7b361
135842339665787
142463d25528769
15102d163b21461
hex7782a71b0b39

131403033021241 has 2 divisors, whose sum is σ = 131403033021242. Its totient is φ = 131403033021240.

The previous prime is 131403033021217. The next prime is 131403033021259. The reversal of 131403033021241 is 142120330304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94602078849600 + 36800954171641 = 9726360^2 + 6066379^2 .

It is an emirp because it is prime and its reverse (142120330304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131403033021241 - 25 = 131403033021209 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403033021541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701516510620 + 65701516510621.

It is an arithmetic number, because the mean of its divisors is an integer number (65701516510621).

Almost surely, 2131403033021241 is an apocalyptic number.

It is an amenable number.

131403033021241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403033021241 is an equidigital number, since it uses as much as digits as its factorization.

131403033021241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131403033021241 its reverse (142120330304131), we get a palindrome (273523363325372).

The spelling of 131403033021241 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-three million, twenty-one thousand, two hundred forty-one".