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13140311412335 = 53796934201273
BaseRepresentation
bin1011111100110111011110…
…0110000000111001101111
31201112012102220011210102212
42333031313212000321233
53210242324210143320
643540324205041035
72524233111051362
oct277156746007157
951465386153385
1013140311412335
1142068582525a8
12158281b85617b
13744183c12863
14335dccb580d9
1517bc228bd9c5
hexbf377980e6f

13140311412335 has 8 divisors (see below), whose sum is σ = 15809978904720. Its totient is φ = 10484512323264.

The previous prime is 13140311412227. The next prime is 13140311412343. The reversal of 13140311412335 is 53321411304131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13140311412335 - 28 = 13140311412079 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3467098742 + ... + 3467102531.

It is an arithmetic number, because the mean of its divisors is an integer number (1976247363090).

Almost surely, 213140311412335 is an apocalyptic number.

13140311412335 is a deficient number, since it is larger than the sum of its proper divisors (2669667492385).

13140311412335 is an equidigital number, since it uses as much as digits as its factorization.

13140311412335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6934201657.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 13140311412335 its reverse (53321411304131), we get a palindrome (66461722716466).

The spelling of 13140311412335 in words is "thirteen trillion, one hundred forty billion, three hundred eleven million, four hundred twelve thousand, three hundred thirty-five".

Divisors: 1 5 379 1895 6934201273 34671006365 2628062282467 13140311412335