Base | Representation |
---|---|
bin | 10011000111110010010… |
… | …111001011110011111011 |
3 | 11122121202002111201101211 |
4 | 103013302113023303323 |
5 | 133012113441023433 |
6 | 2443354012423551 |
7 | 163635626550553 |
oct | 23076227136373 |
9 | 4577662451354 |
10 | 1314031189243 |
11 | 467306393363 |
12 | 192802477bb7 |
13 | 96bb3006696 |
14 | 47856c60163 |
15 | 242aab698cd |
hex | 131f25cbcfb |
1314031189243 has 2 divisors, whose sum is σ = 1314031189244. Its totient is φ = 1314031189242.
The previous prime is 1314031189181. The next prime is 1314031189259. The reversal of 1314031189243 is 3429811304131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314031189243 - 233 = 1305441254651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314031189196 and 1314031189205.
It is not a weakly prime, because it can be changed into another prime (1314031189043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657015594621 + 657015594622.
It is an arithmetic number, because the mean of its divisors is an integer number (657015594622).
Almost surely, 21314031189243 is an apocalyptic number.
1314031189243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314031189243 is an equidigital number, since it uses as much as digits as its factorization.
1314031189243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 1314031189243 in words is "one trillion, three hundred fourteen billion, thirty-one million, one hundred eighty-nine thousand, two hundred forty-three".
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