131403315120255 has 12 divisors (see below), whose sum is σ = 227765746208520. Its totient is φ = 70081768064112.

The previous prime is 131403315120251. The next prime is 131403315120271. The reversal of 131403315120255 is 552021513304131.

It is a happy number.

131403315120255 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 331 + 51 + 20 + 255 = 666.

It is not a de Polignac number, because 131403315120255 - 2² = 131403315120251 is a prime.

It is a super-2 number, since 2×131403315120255² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131403315120251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1460036834625 + ... + 1460036834714.

It is an arithmetic number, because the mean of its divisors is an integer number (18980478850710).

Almost surely, 2^{131403315120255} is an apocalyptic number.

131403315120255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131403315120255 is a deficient number, since it is larger than the sum of its proper divisors (96362431088265).

131403315120255 is a wasteful number, since it uses less digits than its factorization.

131403315120255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2920073669350 (or 2920073669347 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 36.

Adding to 131403315120255 its reverse (552021513304131), we get a palindrome (683424828424386).

The spelling of 131403315120255 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred fifteen million, one hundred twenty thousand, two hundred fifty-five".