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13140342550462 = 2157249711675873
BaseRepresentation
bin1011111100110111100101…
…1100110010111110111110
31201112012112001202202220211
42333031321130302332332
53210242410143103322
643540331240303034
72524233636530161
oct277157134627676
951465461682824
1013140342550462
114206873890096
12158282a171a7a
1374418a4c589a
14335dd2d41ad8
1517bc254beb77
hexbf379732fbe

13140342550462 has 16 divisors (see below), whose sum is σ = 19836864700272. Its totient is φ = 6528057719040.

The previous prime is 13140342550421. The next prime is 13140342550463. The reversal of 13140342550462 is 26405524304131.

It is a super-3 number, since 3×131403425504623 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140342550463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7002958 + ... + 8678830.

It is an arithmetic number, because the mean of its divisors is an integer number (1239804043767).

Almost surely, 213140342550462 is an apocalyptic number.

13140342550462 is a deficient number, since it is larger than the sum of its proper divisors (6696522149810).

13140342550462 is a wasteful number, since it uses less digits than its factorization.

13140342550462 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1701003.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 13140342550462 its reverse (26405524304131), we get a palindrome (39545866854593).

The spelling of 13140342550462 in words is "thirteen trillion, one hundred forty billion, three hundred forty-two million, five hundred fifty thousand, four hundred sixty-two".

Divisors: 1 2 157 314 24971 49942 1675873 3351746 3920447 7840894 263112061 526224122 41848224683 83696449366 6570171275231 13140342550462