Base | Representation |
---|---|
bin | 11101111000001010111111… |
… | …000000100010111011001111 |
3 | 122020021001020020202122120112 |
4 | 131320022333000202323033 |
5 | 114210403213103421020 |
6 | 1143245523152110235 |
7 | 36451404410233100 |
oct | 3570127700427317 |
9 | 566231206678515 |
10 | 131403434045135 |
11 | 3896197992444a |
12 | 128a2a4823537b |
13 | 58423a1775115 |
14 | 2463d628b83a7 |
15 | 102d188e382c5 |
hex | 7782bf022ecf |
131403434045135 has 24 divisors (see below), whose sum is σ = 186011966677536. Its totient is φ = 88836124413120.
The previous prime is 131403434045123. The next prime is 131403434045153. The reversal of 131403434045135 is 531540434304131.
It is not a de Polignac number, because 131403434045135 - 210 = 131403434044111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131403434045092 and 131403434045101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3777028712 + ... + 3777063501.
It is an arithmetic number, because the mean of its divisors is an integer number (7750498611564).
Almost surely, 2131403434045135 is an apocalyptic number.
131403434045135 is a deficient number, since it is larger than the sum of its proper divisors (54608532632401).
131403434045135 is an equidigital number, since it uses as much as digits as its factorization.
131403434045135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7554092303 (or 7554092296 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 131403434045135 its reverse (531540434304131), we get a palindrome (662943868349266).
The spelling of 131403434045135 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-four million, forty-five thousand, one hundred thirty-five".
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