Base | Representation |
---|---|
bin | 1011111100110111100111… |
… | …1101111110111001001111 |
3 | 1201112012112200010202102220 |
4 | 2333031321331332321033 |
5 | 3210242414404444444 |
6 | 43540332150550423 |
7 | 2524234103502231 |
oct | 277157175767117 |
9 | 51465480122386 |
10 | 13140351249999 |
11 | 4206878792196 |
12 | 1582831068413 |
13 | 74418c25053c |
14 | 335dd4168251 |
15 | 17bc2613c619 |
hex | bf379f7ee4f |
13140351249999 has 16 divisors (see below), whose sum is σ = 17543434325760. Its totient is φ = 8748753654080.
The previous prime is 13140351249967. The next prime is 13140351250007. The reversal of 13140351249999 is 99994215304131.
It is a cyclic number.
It is not a de Polignac number, because 13140351249999 - 25 = 13140351249967 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140351249959) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21181864 + ... + 21793394.
It is an arithmetic number, because the mean of its divisors is an integer number (1096464645360).
Almost surely, 213140351249999 is an apocalyptic number.
13140351249999 is a deficient number, since it is larger than the sum of its proper divisors (4403083075761).
13140351249999 is an equidigital number, since it uses as much as digits as its factorization.
13140351249999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620910.
The product of its (nonzero) digits is 9447840, while the sum is 60.
The spelling of 13140351249999 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-one million, two hundred forty-nine thousand, nine hundred ninety-nine".
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