13140351250007 has 2 divisors, whose sum is σ = 13140351250008. Its totient is φ = 13140351250006.

The previous prime is 13140351249967. The next prime is 13140351250153. The reversal of 13140351250007 is 70005215304131.

It is a weak prime.

It is an emirp because it is prime and its reverse (70005215304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13140351250007 - 2²⁰ = 13140350201431 is a prime.

It is a super-3 number, since 3×13140351250007³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140351258007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570175625003 + 6570175625004.

It is an arithmetic number, because the mean of its divisors is an integer number (6570175625004).

Almost surely, 2^{13140351250007} is an apocalyptic number.

13140351250007 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140351250007 is an equidigital number, since it uses as much as digits as its factorization.

13140351250007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12600, while the sum is 32.

Adding to 13140351250007 its reverse (70005215304131), we get a palindrome (83145566554138).

The spelling of 13140351250007 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-one million, two hundred fifty thousand, seven".