Base | Representation |
---|---|
bin | 1011111100110111100111… |
… | …1110001011110111011111 |
3 | 1201112012112200020110022220 |
4 | 2333031321332023313133 |
5 | 3210242414413200020 |
6 | 43540332152040423 |
7 | 2524234104113160 |
oct | 277157176136737 |
9 | 51465480213286 |
10 | 13140351303135 |
11 | 4206878819101 |
12 | 1582831093113 |
13 | 74418c26b794 |
14 | 335dd417d767 |
15 | 17bc2614d240 |
hex | bf379f8bddf |
13140351303135 has 32 divisors (see below), whose sum is σ = 24030529439232. Its totient is φ = 6006403117440.
The previous prime is 13140351303089. The next prime is 13140351303197. The reversal of 13140351303135 is 53130315304131.
It is not a de Polignac number, because 13140351303135 - 28 = 13140351302879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13140351303096 and 13140351303105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5370409 + ... + 7424418.
It is an arithmetic number, because the mean of its divisors is an integer number (750954044976).
Almost surely, 213140351303135 is an apocalyptic number.
13140351303135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13140351303135 is a deficient number, since it is larger than the sum of its proper divisors (10890178136097).
13140351303135 is a wasteful number, since it uses less digits than its factorization.
13140351303135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12804623.
The product of its (nonzero) digits is 24300, while the sum is 33.
Adding to 13140351303135 its reverse (53130315304131), we get a palindrome (66270666607266).
The spelling of 13140351303135 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-one million, three hundred three thousand, one hundred thirty-five".
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