Base | Representation |
---|---|
bin | 11101111000001011000110… |
… | …000111111110101000100111 |
3 | 122020021001112120102020111221 |
4 | 131320023012013332220213 |
5 | 114210403434134343101 |
6 | 1143245543055041211 |
7 | 36451410360101035 |
oct | 3570130607765047 |
9 | 566231476366457 |
10 | 131403553434151 |
11 | 38961a30259159 |
12 | 128a2a80210207 |
13 | 58423c0416bcb |
14 | 2463d746b5555 |
15 | 102d19466caa1 |
hex | 7782c61fea27 |
131403553434151 has 16 divisors (see below), whose sum is σ = 135518046390144. Its totient is φ = 127346208804864.
The previous prime is 131403553434143. The next prime is 131403553434157. The reversal of 131403553434151 is 151434355304131.
It is a cyclic number.
It is not a de Polignac number, because 131403553434151 - 23 = 131403553434143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131403553434098 and 131403553434107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131403553434157) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6489426 + ... + 17461951.
It is an arithmetic number, because the mean of its divisors is an integer number (8469877899384).
Almost surely, 2131403553434151 is an apocalyptic number.
131403553434151 is a deficient number, since it is larger than the sum of its proper divisors (4114492955993).
131403553434151 is a wasteful number, since it uses less digits than its factorization.
131403553434151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23952570.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 131403553434151 in words is "one hundred thirty-one trillion, four hundred three billion, five hundred fifty-three million, four hundred thirty-four thousand, one hundred fifty-one".
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