Base | Representation |
---|---|
bin | 11101111000001011100011… |
… | …001001001111011100010001 |
3 | 122020021002210111112210221102 |
4 | 131320023203021033130101 |
5 | 114210410433304220101 |
6 | 1143250103250234145 |
7 | 36451425421321604 |
oct | 3570134311173421 |
9 | 566232714483842 |
10 | 131404040304401 |
11 | 38962160067a67 |
12 | 128a2b97285955 |
13 | 584246a252a07 |
14 | 2463dbd21033b |
15 | 102d1c229086b |
hex | 7782e324f711 |
131404040304401 has 2 divisors, whose sum is σ = 131404040304402. Its totient is φ = 131404040304400.
The previous prime is 131404040304359. The next prime is 131404040304409. The reversal of 131404040304401 is 104403040404131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113606180304400 + 17797860000001 = 10658620^2 + 4218751^2 .
It is a cyclic number.
It is not a de Polignac number, because 131404040304401 - 210 = 131404040303377 is a prime.
It is not a weakly prime, because it can be changed into another prime (131404040304409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702020152200 + 65702020152201.
It is an arithmetic number, because the mean of its divisors is an integer number (65702020152201).
Almost surely, 2131404040304401 is an apocalyptic number.
It is an amenable number.
131404040304401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131404040304401 is an equidigital number, since it uses as much as digits as its factorization.
131404040304401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 131404040304401 its reverse (104403040404131), we get a palindrome (235807080708532).
The spelling of 131404040304401 in words is "one hundred thirty-one trillion, four hundred four billion, forty million, three hundred four thousand, four hundred one".
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