131404122222242 has 4 divisors (see below), whose sum is σ = 197106183333366. Its totient is φ = 65702061111120.

The previous prime is 131404122222223. The next prime is 131404122222277. The reversal of 131404122222242 is 242222221404131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131401079706961 + 3042515281 = 11463031^2 + 55159^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131404122222199 and 131404122222208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32851030555559 + ... + 32851030555562.

Almost surely, 2^{131404122222242} is an apocalyptic number.

131404122222242 is a deficient number, since it is larger than the sum of its proper divisors (65702061111124).

131404122222242 is an equidigital number, since it uses as much as digits as its factorization.

131404122222242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65702061111123.

The product of its (nonzero) digits is 24576, while the sum is 32.

Adding to 131404122222242 its reverse (242222221404131), we get a palindrome (373626343626373).

The spelling of 131404122222242 in words is "one hundred thirty-one trillion, four hundred four billion, one hundred twenty-two million, two hundred twenty-two thousand, two hundred forty-two".