Base | Representation |
---|---|
bin | 11101111000001011111001… |
… | …010110010110110011011011 |
3 | 122020021010202110112122022212 |
4 | 131320023321112112303123 |
5 | 114210412214141404204 |
6 | 1143250204235105335 |
7 | 36451440563661632 |
oct | 3570137126266333 |
9 | 566233673478285 |
10 | 131404412841179 |
11 | 389623313853a5 |
12 | 128a307bba224b |
13 | 58424c9499b8a |
14 | 24640168a6519 |
15 | 102d1e4d2bc6e |
hex | 7782f9596cdb |
131404412841179 has 2 divisors, whose sum is σ = 131404412841180. Its totient is φ = 131404412841178.
The previous prime is 131404412841127. The next prime is 131404412841241. The reversal of 131404412841179 is 971148214404131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131404412841179 - 220 = 131404411792603 is a prime.
It is a super-2 number, since 2×1314044128411792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131404412841109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702206420589 + 65702206420590.
It is an arithmetic number, because the mean of its divisors is an integer number (65702206420590).
Almost surely, 2131404412841179 is an apocalyptic number.
131404412841179 is a deficient number, since it is larger than the sum of its proper divisors (1).
131404412841179 is an equidigital number, since it uses as much as digits as its factorization.
131404412841179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 774144, while the sum is 50.
The spelling of 131404412841179 in words is "one hundred thirty-one trillion, four hundred four billion, four hundred twelve million, eight hundred forty-one thousand, one hundred seventy-nine".
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