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1314044523521 is a prime number
BaseRepresentation
bin10011000111110011001…
…010000011010000000001
311122121210000121011120222
4103013303022003100001
5133012130344223041
62443355210312425
7163636151105162
oct23076312032001
94577700534528
101314044523521
11467312970624
12192806a28715
1396bb59c4aa2
1447858931769
15242abe0074b
hex131f3283401

1314044523521 has 2 divisors, whose sum is σ = 1314044523522. Its totient is φ = 1314044523520.

The previous prime is 1314044523511. The next prime is 1314044523553. The reversal of 1314044523521 is 1253254404131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 820066080625 + 493978442896 = 905575^2 + 702836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314044523521 - 214 = 1314044507137 is a prime.

It is a super-3 number, since 3×13140445235213 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1314044523511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022261760 + 657022261761.

It is an arithmetic number, because the mean of its divisors is an integer number (657022261761).

Almost surely, 21314044523521 is an apocalyptic number.

It is an amenable number.

1314044523521 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314044523521 is an equidigital number, since it uses as much as digits as its factorization.

1314044523521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 1314044523521 its reverse (1253254404131), we get a palindrome (2567298927652).

The spelling of 1314044523521 in words is "one trillion, three hundred fourteen billion, forty-four million, five hundred twenty-three thousand, five hundred twenty-one".