Base | Representation |
---|---|
bin | 10011000111110011001… |
… | …101001111010000011011 |
3 | 11122121210002011121211111 |
4 | 103013303031033100123 |
5 | 133012131102443011 |
6 | 2443355240241151 |
7 | 163636161155311 |
oct | 23076315172033 |
9 | 4577702147744 |
10 | 1314045359131 |
11 | 46731339140a |
12 | 1928071701b7 |
13 | 96bb5c2822b |
14 | 47858aac0b1 |
15 | 242ac018121 |
hex | 131f334f41b |
1314045359131 has 2 divisors, whose sum is σ = 1314045359132. Its totient is φ = 1314045359130.
The previous prime is 1314045359119. The next prime is 1314045359141. The reversal of 1314045359131 is 1319535404131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314045359131 - 237 = 1176606405659 is a prime.
It is a super-2 number, since 2×13140453591312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314045359141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022679565 + 657022679566.
It is an arithmetic number, because the mean of its divisors is an integer number (657022679566).
Almost surely, 21314045359131 is an apocalyptic number.
1314045359131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314045359131 is an equidigital number, since it uses as much as digits as its factorization.
1314045359131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 1314045359131 in words is "one trillion, three hundred fourteen billion, forty-five million, three hundred fifty-nine thousand, one hundred thirty-one".
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