Base | Representation |
---|---|
bin | 10011000111110011001… |
… | …101100110010001111001 |
3 | 11122121210002100102012011 |
4 | 103013303031212101321 |
5 | 133012131114002213 |
6 | 2443355242245521 |
7 | 163636162030246 |
oct | 23076315462171 |
9 | 4577702312164 |
10 | 1314045453433 |
11 | 467313446249 |
12 | 1928071b68a1 |
13 | 96bb5c5c12b |
14 | 47858ad45cd |
15 | 242ac03603d |
hex | 131f3366479 |
1314045453433 has 2 divisors, whose sum is σ = 1314045453434. Its totient is φ = 1314045453432.
The previous prime is 1314045453389. The next prime is 1314045453521. The reversal of 1314045453433 is 3343545404131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 911971520784 + 402073932649 = 954972^2 + 634093^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314045453433 - 29 = 1314045452921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314045453233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022726716 + 657022726717.
It is an arithmetic number, because the mean of its divisors is an integer number (657022726717).
Almost surely, 21314045453433 is an apocalyptic number.
It is an amenable number.
1314045453433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314045453433 is an equidigital number, since it uses as much as digits as its factorization.
1314045453433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 40.
The spelling of 1314045453433 in words is "one trillion, three hundred fourteen billion, forty-five million, four hundred fifty-three thousand, four hundred thirty-three".
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