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131404555201 is a prime number
BaseRepresentation
bin111101001100001010…
…0100110001111000001
3110120011210212001010211
41322120110212033001
54123104031231301
6140211051354121
712331220201323
oct1723024461701
9416153761124
10131404555201
115080149a257
1221573152941
13c511b8979a
146507c45613
153641308051
hex1e985263c1

131404555201 has 2 divisors, whose sum is σ = 131404555202. Its totient is φ = 131404555200.

The previous prime is 131404555151. The next prime is 131404555207. The reversal of 131404555201 is 102555404131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124220297601 + 7184257600 = 352449^2 + 84760^2 .

It is a cyclic number.

It is not a de Polignac number, because 131404555201 - 225 = 131371000769 is a prime.

It is not a weakly prime, because it can be changed into another prime (131404555207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702277600 + 65702277601.

It is an arithmetic number, because the mean of its divisors is an integer number (65702277601).

Almost surely, 2131404555201 is an apocalyptic number.

It is an amenable number.

131404555201 is a deficient number, since it is larger than the sum of its proper divisors (1).

131404555201 is an equidigital number, since it uses as much as digits as its factorization.

131404555201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 131404555201 its reverse (102555404131), we get a palindrome (233959959332).

The spelling of 131404555201 in words is "one hundred thirty-one billion, four hundred four million, five hundred fifty-five thousand, two hundred one".