Base | Representation |
---|---|
bin | 10011000111110011011… |
… | …011110100001101111001 |
3 | 11122121210100100202211001 |
4 | 103013303123310031321 |
5 | 133012133042234122 |
6 | 2443355454205001 |
7 | 163636235512402 |
oct | 23076333641571 |
9 | 4577710322731 |
10 | 1314049180537 |
11 | 4673155614a5 |
12 | 1928084b3761 |
13 | 96bb6965712 |
14 | 478593c49a9 |
15 | 242ac520527 |
hex | 131f36f4379 |
1314049180537 has 2 divisors, whose sum is σ = 1314049180538. Its totient is φ = 1314049180536.
The previous prime is 1314049180513. The next prime is 1314049180547. The reversal of 1314049180537 is 7350819404131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 740983526416 + 573065654121 = 860804^2 + 757011^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314049180537 - 235 = 1279689442169 is a prime.
It is a super-2 number, since 2×13140491805372 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314049180547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657024590268 + 657024590269.
It is an arithmetic number, because the mean of its divisors is an integer number (657024590269).
Almost surely, 21314049180537 is an apocalyptic number.
It is an amenable number.
1314049180537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314049180537 is an equidigital number, since it uses as much as digits as its factorization.
1314049180537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 1314049180537 in words is "one trillion, three hundred fourteen billion, forty-nine million, one hundred eighty thousand, five hundred thirty-seven".
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