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1314049180537 is a prime number
BaseRepresentation
bin10011000111110011011…
…011110100001101111001
311122121210100100202211001
4103013303123310031321
5133012133042234122
62443355454205001
7163636235512402
oct23076333641571
94577710322731
101314049180537
114673155614a5
121928084b3761
1396bb6965712
14478593c49a9
15242ac520527
hex131f36f4379

1314049180537 has 2 divisors, whose sum is σ = 1314049180538. Its totient is φ = 1314049180536.

The previous prime is 1314049180513. The next prime is 1314049180547. The reversal of 1314049180537 is 7350819404131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 740983526416 + 573065654121 = 860804^2 + 757011^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314049180537 - 235 = 1279689442169 is a prime.

It is a super-2 number, since 2×13140491805372 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1314049180547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657024590268 + 657024590269.

It is an arithmetic number, because the mean of its divisors is an integer number (657024590269).

Almost surely, 21314049180537 is an apocalyptic number.

It is an amenable number.

1314049180537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314049180537 is an equidigital number, since it uses as much as digits as its factorization.

1314049180537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 46.

The spelling of 1314049180537 in words is "one trillion, three hundred fourteen billion, forty-nine million, one hundred eighty thousand, five hundred thirty-seven".