Base | Representation |
---|---|
bin | 1011111100111000001100… |
… | …0101111000000010101011 |
3 | 1201112012221100011012210222 |
4 | 2333032003011320002223 |
5 | 3210243223101022102 |
6 | 43540355255400255 |
7 | 2524240642513106 |
oct | 277160305700253 |
9 | 51465840135728 |
10 | 13140504314027 |
11 | 4206947127492 |
12 | 158287438308b |
13 | 7441b4b82c7c |
14 | 33600a60d73d |
15 | 17bc347c4aa2 |
hex | bf3831780ab |
13140504314027 has 2 divisors, whose sum is σ = 13140504314028. Its totient is φ = 13140504314026.
The previous prime is 13140504313997. The next prime is 13140504314059. The reversal of 13140504314027 is 72041340504131.
13140504314027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140504314027 - 28 = 13140504313771 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140504304027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570252157013 + 6570252157014.
It is an arithmetic number, because the mean of its divisors is an integer number (6570252157014).
Almost surely, 213140504314027 is an apocalyptic number.
13140504314027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140504314027 is an equidigital number, since it uses as much as digits as its factorization.
13140504314027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 13140504314027 its reverse (72041340504131), we get a palindrome (85181844818158).
The spelling of 13140504314027 in words is "thirteen trillion, one hundred forty billion, five hundred four million, three hundred fourteen thousand, twenty-seven".
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