13140504452031 has 32 divisors (see below), whose sum is σ = 19431509160960. Its totient is φ = 7831485379200.

The previous prime is 13140504452011. The next prime is 13140504452051. The reversal of 13140504452031 is 13025440504131.

It is an interprime number because it is at equal distance from previous prime (13140504452011) and next prime (13140504452051).

It is not a de Polignac number, because 13140504452031 - 2⁵ = 13140504451999 is a prime.

It is a super-2 number, since 2×13140504452031² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 13140504451983 and 13140504452001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140504452011) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7530010 + ... + 9109448.

It is an arithmetic number, because the mean of its divisors is an integer number (607234661280).

Almost surely, 2^{13140504452031} is an apocalyptic number.

13140504452031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13140504452031 is a deficient number, since it is larger than the sum of its proper divisors (6291004708929).

13140504452031 is a wasteful number, since it uses less digits than its factorization.

13140504452031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1583647.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13140504452031 its reverse (13025440504131), we get a palindrome (26165944956162).

The spelling of 13140504452031 in words is "thirteen trillion, one hundred forty billion, five hundred four million, four hundred fifty-two thousand, thirty-one".