Base | Representation |
---|---|
bin | 1011111100111000001100… |
… | …0110011001101111010111 |
3 | 1201112012221100102020011010 |
4 | 2333032003012121233113 |
5 | 3210243223114431210 |
6 | 43540355302343303 |
7 | 2524240643626401 |
oct | 277160306315727 |
9 | 51465840366133 |
10 | 13140504452055 |
11 | 4206947211162 |
12 | 158287442ab33 |
13 | 7441b4c00a46 |
14 | 33600a647b71 |
15 | 17bc34800920 |
hex | bf383199bd7 |
13140504452055 has 32 divisors (see below), whose sum is σ = 21074109099264. Its totient is φ = 6991841154816.
The previous prime is 13140504452051. The next prime is 13140504452077. The reversal of 13140504452055 is 55025440504131.
It is not a de Polignac number, because 13140504452055 - 22 = 13140504452051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140504452051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34745859 + ... + 35122011.
It is an arithmetic number, because the mean of its divisors is an integer number (658565909352).
Almost surely, 213140504452055 is an apocalyptic number.
13140504452055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13140504452055 is a deficient number, since it is larger than the sum of its proper divisors (7933604647209).
13140504452055 is a wasteful number, since it uses less digits than its factorization.
13140504452055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 381615.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 13140504452055 its reverse (55025440504131), we get a palindrome (68165944956186).
The spelling of 13140504452055 in words is "thirteen trillion, one hundred forty billion, five hundred four million, four hundred fifty-two thousand, fifty-five".
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