1314051431461 has 4 divisors (see below), whose sum is σ = 1349566335052. Its totient is φ = 1278536527872.

The previous prime is 1314051431453. The next prime is 1314051431467. The reversal of 1314051431461 is 1641341504131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1266793019361 + 47258412100 = 1125519^2 + 217390^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314051431461 - 2³ = 1314051431453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314051431467) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17757451740 + ... + 17757451813.

It is an arithmetic number, because the mean of its divisors is an integer number (337391583763).

Almost surely, 2^{1314051431461} is an apocalyptic number.

It is an amenable number.

1314051431461 is a deficient number, since it is larger than the sum of its proper divisors (35514903591).

1314051431461 is an equidigital number, since it uses as much as digits as its factorization.

1314051431461 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35514903590.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 1314051431461 its reverse (1641341504131), we get a palindrome (2955392935592).

The spelling of 1314051431461 in words is "one trillion, three hundred fourteen billion, fifty-one million, four hundred thirty-one thousand, four hundred sixty-one".