Base | Representation |
---|---|
bin | 111101001100001100… |
… | …0010101000100000101 |
3 | 110120011212200202001002 |
4 | 1322120120111010011 |
5 | 4123104304032240 |
6 | 140211124343045 |
7 | 12331231414334 |
oct | 1723030250405 |
9 | 416155622032 |
10 | 131405533445 |
11 | 50801aa821a |
12 | 21573544a85 |
13 | c51213cb24 |
14 | 650801bd1b |
15 | 364144cd15 |
hex | 1e98615105 |
131405533445 has 4 divisors (see below), whose sum is σ = 157686640140. Its totient is φ = 105124426752.
The previous prime is 131405533423. The next prime is 131405533459. The reversal of 131405533445 is 544335504131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 98516260129 + 32889273316 = 313873^2 + 181354^2 .
It is a cyclic number.
It is not a de Polignac number, because 131405533445 - 210 = 131405532421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131405533399 and 131405533408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13140553340 + ... + 13140553349.
It is an arithmetic number, because the mean of its divisors is an integer number (39421660035).
Almost surely, 2131405533445 is an apocalyptic number.
It is an amenable number.
131405533445 is a deficient number, since it is larger than the sum of its proper divisors (26281106695).
131405533445 is an equidigital number, since it uses as much as digits as its factorization.
131405533445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26281106694.
The product of its (nonzero) digits is 216000, while the sum is 38.
The spelling of 131405533445 in words is "one hundred thirty-one billion, four hundred five million, five hundred thirty-three thousand, four hundred forty-five".
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