Base | Representation |
---|---|
bin | 11000011110011110… |
… | …10001001011100001 |
3 | 1020220210021202011211 |
4 | 30033033101023201 |
5 | 203402441001112 |
6 | 10011531510121 |
7 | 643430640205 |
oct | 141717211341 |
9 | 36823252154 |
10 | 13140562657 |
11 | 5633561242 |
12 | 26688b8341 |
13 | 1315548181 |
14 | 8c92b8b05 |
15 | 51d96a0a7 |
hex | 30f3d12e1 |
13140562657 has 2 divisors, whose sum is σ = 13140562658. Its totient is φ = 13140562656.
The previous prime is 13140562651. The next prime is 13140562661. The reversal of 13140562657 is 75626504131.
13140562657 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12589064401 + 551498256 = 112201^2 + 23484^2 .
It is a cyclic number.
It is not a de Polignac number, because 13140562657 - 23 = 13140562649 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140562651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570281328 + 6570281329.
It is an arithmetic number, because the mean of its divisors is an integer number (6570281329).
Almost surely, 213140562657 is an apocalyptic number.
It is an amenable number.
13140562657 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140562657 is an equidigital number, since it uses as much as digits as its factorization.
13140562657 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 13140562657 in words is "thirteen billion, one hundred forty million, five hundred sixty-two thousand, six hundred fifty-seven".
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