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131406365033 is a prime number
BaseRepresentation
bin111101001100001101…
…1100000000101101001
3110120011221020222202122
41322120123200011221
54123110012140113
6140211154241025
712331241446646
oct1723033400551
9416157228678
10131406365033
1150802515a89
1221573886175
13c5123714a8
146508196dcd
153641564408
hex1e986e0169

131406365033 has 2 divisors, whose sum is σ = 131406365034. Its totient is φ = 131406365032.

The previous prime is 131406365017. The next prime is 131406365039. The reversal of 131406365033 is 330563604131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78021338329 + 53385026704 = 279323^2 + 231052^2 .

It is a cyclic number.

It is not a de Polignac number, because 131406365033 - 24 = 131406365017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131406364984 and 131406365002.

It is not a weakly prime, because it can be changed into another prime (131406365039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65703182516 + 65703182517.

It is an arithmetic number, because the mean of its divisors is an integer number (65703182517).

Almost surely, 2131406365033 is an apocalyptic number.

It is an amenable number.

131406365033 is a deficient number, since it is larger than the sum of its proper divisors (1).

131406365033 is an equidigital number, since it uses as much as digits as its factorization.

131406365033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 35.

Adding to 131406365033 its reverse (330563604131), we get a palindrome (461969969164).

The spelling of 131406365033 in words is "one hundred thirty-one billion, four hundred six million, three hundred sixty-five thousand, thirty-three".