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13141002412201 is a prime number
BaseRepresentation
bin1011111100111010000011…
…0001111110000010101001
31201112021020001102020001111
42333032200301332002221
53210300233104142301
643540520531350321
72524256201336266
oct277164061760251
951467201366044
1013141002412201
114207082304a74
1215829931523a1
13744264120511
1433605682c26d
1517bc633b4551
hexbf3a0c7e0a9

13141002412201 has 2 divisors, whose sum is σ = 13141002412202. Its totient is φ = 13141002412200.

The previous prime is 13141002412193. The next prime is 13141002412211. The reversal of 13141002412201 is 10221420014131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13128310136601 + 12692275600 = 3623301^2 + 112660^2 .

It is a cyclic number.

It is not a de Polignac number, because 13141002412201 - 23 = 13141002412193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13141002412211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570501206100 + 6570501206101.

It is an arithmetic number, because the mean of its divisors is an integer number (6570501206101).

Almost surely, 213141002412201 is an apocalyptic number.

It is an amenable number.

13141002412201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141002412201 is an equidigital number, since it uses as much as digits as its factorization.

13141002412201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 13141002412201 its reverse (10221420014131), we get a palindrome (23362422426332).

The spelling of 13141002412201 in words is "thirteen trillion, one hundred forty-one billion, two million, four hundred twelve thousand, two hundred one".