Base | Representation |
---|---|
bin | 10011000111110110100… |
… | …110111100111011010011 |
3 | 11122121221001120012022211 |
4 | 103013312212330323103 |
5 | 133012240210301233 |
6 | 2443405035412551 |
7 | 163640453240014 |
oct | 23076646747323 |
9 | 4577831505284 |
10 | 1314102431443 |
11 | 46734262270a |
12 | 1928222b4157 |
13 | 96bc49bb729 |
14 | 478624c700b |
15 | 242b203d5cd |
hex | 131f69bced3 |
1314102431443 has 2 divisors, whose sum is σ = 1314102431444. Its totient is φ = 1314102431442.
The previous prime is 1314102431363. The next prime is 1314102431461. The reversal of 1314102431443 is 3441342014131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314102431443 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314102431143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657051215721 + 657051215722.
It is an arithmetic number, because the mean of its divisors is an integer number (657051215722).
Almost surely, 21314102431443 is an apocalyptic number.
1314102431443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314102431443 is an equidigital number, since it uses as much as digits as its factorization.
1314102431443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1314102431443 its reverse (3441342014131), we get a palindrome (4755444445574).
The spelling of 1314102431443 in words is "one trillion, three hundred fourteen billion, one hundred two million, four hundred thirty-one thousand, four hundred forty-three".
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