131410424121 has 4 divisors (see below), whose sum is σ = 175213898832. Its totient is φ = 87606949412.

The previous prime is 131410424111. The next prime is 131410424143. The reversal of 131410424121 is 121424014131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131410424121 - 2²¹ = 131408326969 is a prime.

It is a super-2 number, since 2×131410424121² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131410424091 and 131410424100.

It is not an unprimeable number, because it can be changed into a prime (131410424111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21901737351 + ... + 21901737356.

It is an arithmetic number, because the mean of its divisors is an integer number (43803474708).

Almost surely, 2^131410424121 is an apocalyptic number.

It is an amenable number.

131410424121 is a deficient number, since it is larger than the sum of its proper divisors (43803474711).

131410424121 is an equidigital number, since it uses as much as digits as its factorization.

131410424121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43803474710.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 131410424121 its reverse (121424014131), we get a palindrome (252834438252).

The spelling of 131410424121 in words is "one hundred thirty-one billion, four hundred ten million, four hundred twenty-four thousand, one hundred twenty-one".