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1314107754961 is a prime number
BaseRepresentation
bin10011000111110110111…
…011010000100111010001
311122121221102120122211011
4103013312323100213101
5133012243041124321
62443405345450521
7163640546421331
oct23076673204721
94577842518734
101314107754961
11467345629311
12192824040a41
1396bc5b33841
14478630b10c1
15242b2740ae1
hex131f6ed09d1

1314107754961 has 2 divisors, whose sum is σ = 1314107754962. Its totient is φ = 1314107754960.

The previous prime is 1314107754923. The next prime is 1314107754989. The reversal of 1314107754961 is 1694577014131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1179396000000 + 134711754961 = 1086000^2 + 367031^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314107754961 - 27 = 1314107754833 is a prime.

It is a super-2 number, since 2×13141077549612 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1314107754901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657053877480 + 657053877481.

It is an arithmetic number, because the mean of its divisors is an integer number (657053877481).

Almost surely, 21314107754961 is an apocalyptic number.

It is an amenable number.

1314107754961 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314107754961 is an equidigital number, since it uses as much as digits as its factorization.

1314107754961 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 635040, while the sum is 49.

The spelling of 1314107754961 in words is "one trillion, three hundred fourteen billion, one hundred seven million, seven hundred fifty-four thousand, nine hundred sixty-one".