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13141220041 is a prime number
BaseRepresentation
bin11000011110100011…
…10001101011001001
31020220211112010221101
430033101301223021
5203403123020131
610011553541401
7643436345605
oct141721615311
936824463841
1013141220041
115633970134
122668b74861
131315718461
148c940a505
1551da49c61
hex30f471ac9

13141220041 has 2 divisors, whose sum is σ = 13141220042. Its totient is φ = 13141220040.

The previous prime is 13141220017. The next prime is 13141220093. The reversal of 13141220041 is 14002214131.

13141220041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7975204416 + 5166015625 = 89304^2 + 71875^2 .

It is a cyclic number.

It is not a de Polignac number, because 13141220041 - 211 = 13141217993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13141220641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570610020 + 6570610021.

It is an arithmetic number, because the mean of its divisors is an integer number (6570610021).

Almost surely, 213141220041 is an apocalyptic number.

It is an amenable number.

13141220041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141220041 is an equidigital number, since it uses as much as digits as its factorization.

13141220041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13141220041 its reverse (14002214131), we get a palindrome (27143434172).

The spelling of 13141220041 in words is "thirteen billion, one hundred forty-one million, two hundred twenty thousand, forty-one".