131412322010041 has 4 divisors (see below), whose sum is σ = 131413419546192. Its totient is φ = 131411224473892.

The previous prime is 131412322009973. The next prime is 131412322010071. The reversal of 131412322010041 is 140010223214131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131412322010041 - 2¹⁵ = 131412321977273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131412322009988 and 131412322010015.

It is not an unprimeable number, because it can be changed into a prime (131412322010071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 548588455 + ... + 548827948.

It is an arithmetic number, because the mean of its divisors is an integer number (32853354886548).

Almost surely, 2^{131412322010041} is an apocalyptic number.

It is an amenable number.

131412322010041 is a deficient number, since it is larger than the sum of its proper divisors (1097536151).

131412322010041 is a wasteful number, since it uses less digits than its factorization.

131412322010041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1097536150.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131412322010041 its reverse (140010223214131), we get a palindrome (271422545224172).

The spelling of 131412322010041 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred twenty-two million, ten thousand, forty-one".