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131412322009973 is a prime number
BaseRepresentation
bin11101111000010011010000…
…110001011100001101110101
3122020021220011200001001020102
4131320103100301130031311
5114211024413413304343
61143253553132043445
736452140562545034
oct3570232061341565
9566256150031212
10131412322009973
113896571a953a34
12128a4708903585
135843189c59904
14246456708871b
15102d5093843b8
hex7784d0c5c375

131412322009973 has 2 divisors, whose sum is σ = 131412322009974. Its totient is φ = 131412322009972.

The previous prime is 131412322009963. The next prime is 131412322010071. The reversal of 131412322009973 is 379900223214131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130887831746884 + 524490263089 = 11440622^2 + 724217^2 .

It is a cyclic number.

It is not a de Polignac number, because 131412322009973 - 26 = 131412322009909 is a prime.

It is a super-2 number, since 2×1314123220099732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131412322009933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706161004986 + 65706161004987.

It is an arithmetic number, because the mean of its divisors is an integer number (65706161004987).

Almost surely, 2131412322009973 is an apocalyptic number.

It is an amenable number.

131412322009973 is a deficient number, since it is larger than the sum of its proper divisors (1).

131412322009973 is an equidigital number, since it uses as much as digits as its factorization.

131412322009973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 47.

The spelling of 131412322009973 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred twenty-two million, nine thousand, nine hundred seventy-three".