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131412322042300 = 2252137331116672671
BaseRepresentation
bin11101111000010011010000…
…110001100100000110111100
3122020021220011200002200120201
4131320103100301210012330
5114211024413420323200
61143253553132453244
736452140563041215
oct3570232061440674
9566256150080521
10131412322042300
113896571a976252
12128a470891a224
135843189c6b540
14246456709640c
15102d50938dc6a
hex7784d0c641bc

131412322042300 has 288 divisors, whose sum is σ = 312612675508224. Its totient is φ = 47656449792000.

The previous prime is 131412322042297. The next prime is 131412322042303. The reversal of 131412322042300 is 3240223214131.

It is an interprime number because it is at equal distance from previous prime (131412322042297) and next prime (131412322042303).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131412322042303) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 49199669965 + ... + 49199672635.

It is an arithmetic number, because the mean of its divisors is an integer number (1085460678848).

Almost surely, 2131412322042300 is an apocalyptic number.

131412322042300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131412322042300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156306337754112).

131412322042300 is an abundant number, since it is smaller than the sum of its proper divisors (181200353465924).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131412322042300 is a wasteful number, since it uses less digits than its factorization.

131412322042300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4749 (or 4742 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 131412322042300 its reverse (3240223214131), we get a palindrome (134652545256431).

The spelling of 131412322042300 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred twenty-two million, forty-two thousand, three hundred".