Base | Representation |
---|---|
bin | 1011111100111010111100… |
… | …0001010110011011110111 |
3 | 1201112021211200222021012220 |
4 | 2333032233001112123313 |
5 | 3210301230234402203 |
6 | 43541000344213423 |
7 | 2524265132144040 |
oct | 277165701263367 |
9 | 51467750867186 |
10 | 13141241325303 |
11 | 4207195155a13 |
12 | 1582a3b16a273 |
13 | 7442a1780710 |
14 | 33607a45d8c7 |
15 | 17bc79358653 |
hex | bf3af0566f7 |
13141241325303 has 32 divisors (see below), whose sum is σ = 21570901825536. Its totient is φ = 6929783394048.
The previous prime is 13141241325229. The next prime is 13141241325307. The reversal of 13141241325303 is 30352314214131.
It is not a de Polignac number, because 13141241325303 - 212 = 13141241321207 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13141241325307) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5440326 + ... + 7475267.
It is an arithmetic number, because the mean of its divisors is an integer number (674090682048).
Almost surely, 213141241325303 is an apocalyptic number.
13141241325303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13141241325303 is a deficient number, since it is larger than the sum of its proper divisors (8429660500233).
13141241325303 is a wasteful number, since it uses less digits than its factorization.
13141241325303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12919343.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 13141241325303 its reverse (30352314214131), we get a palindrome (43493555539434).
The spelling of 13141241325303 in words is "thirteen trillion, one hundred forty-one billion, two hundred forty-one million, three hundred twenty-five thousand, three hundred three".
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