Base | Representation |
---|---|
bin | 1011111100111010111110… |
… | …0110110110000010000001 |
3 | 1201112021212101110121201112 |
4 | 2333032233212312002001 |
5 | 3210301240243412144 |
6 | 43541001335013105 |
7 | 2524265311531214 |
oct | 277165746660201 |
9 | 51467771417645 |
10 | 13141251154049 |
11 | 420719a759447 |
12 | 1582a4250a195 |
13 | 7442a3812345 |
14 | 33607b89b77b |
15 | 17bc7a14a99e |
hex | bf3af9b6081 |
13141251154049 has 2 divisors, whose sum is σ = 13141251154050. Its totient is φ = 13141251154048.
The previous prime is 13141251153991. The next prime is 13141251154063. The reversal of 13141251154049 is 94045115214131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11219867054449 + 1921384099600 = 3349607^2 + 1386140^2 .
It is a cyclic number.
It is not a de Polignac number, because 13141251154049 - 228 = 13140982718593 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13141251153997 and 13141251154015.
It is not a weakly prime, because it can be changed into another prime (13141251153049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570625577024 + 6570625577025.
It is an arithmetic number, because the mean of its divisors is an integer number (6570625577025).
Almost surely, 213141251154049 is an apocalyptic number.
It is an amenable number.
13141251154049 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141251154049 is an equidigital number, since it uses as much as digits as its factorization.
13141251154049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 41.
The spelling of 13141251154049 in words is "thirteen trillion, one hundred forty-one billion, two hundred fifty-one million, one hundred fifty-four thousand, forty-nine".
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