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13141300402214 = 26570650201107
BaseRepresentation
bin1011111100111011001010…
…0010101101100000100110
31201112021222211010200111122
42333032302202231200212
53210301340400332324
643541010254333542
72524266450244655
oct277166242554046
951467884120448
1013141300402214
114207215536306
121582a56aba2b2
137442b0a9647a
1433608423b19c
1517bc7e627a5e
hexbf3b28ad826

13141300402214 has 4 divisors (see below), whose sum is σ = 19711950603324. Its totient is φ = 6570650201106.

The previous prime is 13141300402201. The next prime is 13141300402249. The reversal of 13141300402214 is 41220400314131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131413004022142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285325100552 + ... + 3285325100555.

It is an arithmetic number, because the mean of its divisors is an integer number (4927987650831).

Almost surely, 213141300402214 is an apocalyptic number.

13141300402214 is a deficient number, since it is larger than the sum of its proper divisors (6570650201110).

13141300402214 is an equidigital number, since it uses as much as digits as its factorization.

13141300402214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6570650201109.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 13141300402214 its reverse (41220400314131), we get a palindrome (54361700716345).

The spelling of 13141300402214 in words is "thirteen trillion, one hundred forty-one billion, three hundred million, four hundred two thousand, two hundred fourteen".

Divisors: 1 2 6570650201107 13141300402214