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13141303530455 = 52628260706091
BaseRepresentation
bin1011111100111011001010…
…1110101001001111010111
31201112022000001000121122102
42333032302232221033113
53210301342200433310
643541010445352315
72524266515654132
oct277166256511727
951468001017572
1013141303530455
114207217282631
121582a57b6869b
137442b16202b9
14336084813219
1517bc7ea448a5
hexbf3b2ba93d7

13141303530455 has 4 divisors (see below), whose sum is σ = 15769564236552. Its totient is φ = 10513042824360.

The previous prime is 13141303530401. The next prime is 13141303530457. The reversal of 13141303530455 is 55403530314131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13141303530455 - 26 = 13141303530391 is a prime.

It is a super-2 number, since 2×131413035304552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13141303530457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314130353041 + ... + 1314130353050.

It is an arithmetic number, because the mean of its divisors is an integer number (3942391059138).

Almost surely, 213141303530455 is an apocalyptic number.

13141303530455 is a deficient number, since it is larger than the sum of its proper divisors (2628260706097).

13141303530455 is an equidigital number, since it uses as much as digits as its factorization.

13141303530455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2628260706096.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 13141303530455 its reverse (55403530314131), we get a palindrome (68544833844586).

The spelling of 13141303530455 in words is "thirteen trillion, one hundred forty-one billion, three hundred three million, five hundred thirty thousand, four hundred fifty-five".

Divisors: 1 5 2628260706091 13141303530455