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13141304045011 = 43305611721977
BaseRepresentation
bin1011111100111011001011…
…0000100110110111010011
31201112022000001222202111001
42333032302300212313103
53210301342313420021
643541010504402431
72524266523226242
oct277166260466723
951468001882431
1013141304045011
1142072175a418a
121582a58176417
137442b177057c
14336084908959
1517bc7eae7091
hexbf3b2c26dd3

13141304045011 has 4 divisors (see below), whose sum is σ = 13446915767032. Its totient is φ = 12835692322992.

The previous prime is 13141304044993. The next prime is 13141304045027. The reversal of 13141304045011 is 11054040314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13141304045011 - 217 = 13141303913939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13141304045071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152805860946 + ... + 152805861031.

It is an arithmetic number, because the mean of its divisors is an integer number (3361728941758).

Almost surely, 213141304045011 is an apocalyptic number.

13141304045011 is a deficient number, since it is larger than the sum of its proper divisors (305611722021).

13141304045011 is an equidigital number, since it uses as much as digits as its factorization.

13141304045011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 305611722020.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13141304045011 its reverse (11054040314131), we get a palindrome (24195344359142).

The spelling of 13141304045011 in words is "thirteen trillion, one hundred forty-one billion, three hundred four million, forty-five thousand, eleven".

Divisors: 1 43 305611721977 13141304045011