Base | Representation |
---|---|
bin | 1011111100111011001011… |
… | …0000100110110111010011 |
3 | 1201112022000001222202111001 |
4 | 2333032302300212313103 |
5 | 3210301342313420021 |
6 | 43541010504402431 |
7 | 2524266523226242 |
oct | 277166260466723 |
9 | 51468001882431 |
10 | 13141304045011 |
11 | 42072175a418a |
12 | 1582a58176417 |
13 | 7442b177057c |
14 | 336084908959 |
15 | 17bc7eae7091 |
hex | bf3b2c26dd3 |
13141304045011 has 4 divisors (see below), whose sum is σ = 13446915767032. Its totient is φ = 12835692322992.
The previous prime is 13141304044993. The next prime is 13141304045027. The reversal of 13141304045011 is 11054040314131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13141304045011 - 217 = 13141303913939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13141304045071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152805860946 + ... + 152805861031.
It is an arithmetic number, because the mean of its divisors is an integer number (3361728941758).
Almost surely, 213141304045011 is an apocalyptic number.
13141304045011 is a deficient number, since it is larger than the sum of its proper divisors (305611722021).
13141304045011 is an equidigital number, since it uses as much as digits as its factorization.
13141304045011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305611722020.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 13141304045011 its reverse (11054040314131), we get a palindrome (24195344359142).
The spelling of 13141304045011 in words is "thirteen trillion, one hundred forty-one billion, three hundred four million, forty-five thousand, eleven".
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