Base | Representation |
---|---|
bin | 1011111100111011001011… |
… | …0000100110111000001111 |
3 | 1201112022000001222202120021 |
4 | 2333032302300212320033 |
5 | 3210301342313420241 |
6 | 43541010504403011 |
7 | 2524266523226356 |
oct | 277166260467017 |
9 | 51468001882507 |
10 | 13141304045071 |
11 | 42072175a4234 |
12 | 1582a58176467 |
13 | 7442b17705c7 |
14 | 33608490899d |
15 | 17bc7eae70d1 |
hex | bf3b2c26e0f |
13141304045071 has 2 divisors, whose sum is σ = 13141304045072. Its totient is φ = 13141304045070.
The previous prime is 13141304045027. The next prime is 13141304045081. The reversal of 13141304045071 is 17054040314131.
It is a strong prime.
It is an emirp because it is prime and its reverse (17054040314131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13141304045071 - 29 = 13141304044559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141304045081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570652022535 + 6570652022536.
It is an arithmetic number, because the mean of its divisors is an integer number (6570652022536).
Almost surely, 213141304045071 is an apocalyptic number.
13141304045071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141304045071 is an equidigital number, since it uses as much as digits as its factorization.
13141304045071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 13141304045071 in words is "thirteen trillion, one hundred forty-one billion, three hundred four million, forty-five thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •