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11054040314131 is a prime number
BaseRepresentation
bin1010000011011011100000…
…1001010111000100010011
31110010202102002001001222101
42200312320021113010103
52422102133310023011
635302053411021231
72220425265236503
oct240667011270423
943122362031871
1011054040314131
113581aa0640851
1212a641b89a817
1362251225bca9
142a3038711a03
1514281aad92c1
hexa0db8257113

11054040314131 has 2 divisors, whose sum is σ = 11054040314132. Its totient is φ = 11054040314130.

The previous prime is 11054040314117. The next prime is 11054040314137. The reversal of 11054040314131 is 13141304045011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11054040314131 - 239 = 10504284500243 is a prime.

It is a super-2 number, since 2×110540403141312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11054040314131.

It is not a weakly prime, because it can be changed into another prime (11054040314137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5527020157065 + 5527020157066.

It is an arithmetic number, because the mean of its divisors is an integer number (5527020157066).

Almost surely, 211054040314131 is an apocalyptic number.

11054040314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11054040314131 is an equidigital number, since it uses as much as digits as its factorization.

11054040314131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 11054040314131 its reverse (13141304045011), we get a palindrome (24195344359142).

The spelling of 11054040314131 in words is "eleven trillion, fifty-four billion, forty million, three hundred fourteen thousand, one hundred thirty-one".