131413111413341 has 4 divisors (see below), whose sum is σ = 131413546428000. Its totient is φ = 131412676398684.

The previous prime is 131413111413323. The next prime is 131413111413401. The reversal of 131413111413341 is 143314111314131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131413111413341 - 2⁴² = 127015064902237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131413111413298 and 131413111413307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131413111413641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217053881 + ... + 217658478.

It is an arithmetic number, because the mean of its divisors is an integer number (32853386607000).

Almost surely, 2^{131413111413341} is an apocalyptic number.

It is an amenable number.

131413111413341 is a deficient number, since it is larger than the sum of its proper divisors (435014659).

131413111413341 is an equidigital number, since it uses as much as digits as its factorization.

131413111413341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 435014658.

The product of its digits is 5184, while the sum is 32.

Adding to 131413111413341 its reverse (143314111314131), we get a palindrome (274727222727472).

The spelling of 131413111413341 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred eleven million, four hundred thirteen thousand, three hundred forty-one".