131413113021313 has 2 divisors, whose sum is σ = 131413113021314. Its totient is φ = 131413113021312.

The previous prime is 131413113021287. The next prime is 131413113021331. The reversal of 131413113021313 is 313120311314131.

Together with next prime (131413113021331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126685649942784 + 4727463078529 = 11255472^2 + 2174273^2 .

It is an emirp because it is prime and its reverse (313120311314131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131413113021313 - 2³³ = 131404523086721 is a prime.

It is a super-3 number, since 3×131413113021313³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (131413113021713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706556510656 + 65706556510657.

It is an arithmetic number, because the mean of its divisors is an integer number (65706556510657).

Almost surely, 2^{131413113021313} is an apocalyptic number.

It is an amenable number.

131413113021313 is a deficient number, since it is larger than the sum of its proper divisors (1).

131413113021313 is an equidigital number, since it uses as much as digits as its factorization.

131413113021313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 28.

Adding to 131413113021313 its reverse (313120311314131), we get a palindrome (444533424335444).

The spelling of 131413113021313 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred thirteen million, twenty-one thousand, three hundred thirteen".