Base | Representation |
---|---|
bin | 1011111100111011001101… |
… | …0000010011011100010011 |
3 | 1201112022000122121220100212 |
4 | 2333032303100103130103 |
5 | 3210301401430312232 |
6 | 43541011402434335 |
7 | 2524266653654012 |
oct | 277166320233423 |
9 | 51468018556325 |
10 | 13141312354067 |
11 | 4207221259977 |
12 | 1582a5ab029ab |
13 | 7442b33bc581 |
14 | 336085a6ca79 |
15 | 17bc806d8eb2 |
hex | bf3b3413713 |
13141312354067 has 2 divisors, whose sum is σ = 13141312354068. Its totient is φ = 13141312354066.
The previous prime is 13141312354061. The next prime is 13141312354249. The reversal of 13141312354067 is 76045321314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141312354067 - 26 = 13141312354003 is a prime.
It is not a weakly prime, because it can be changed into another prime (13141312354061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570656177033 + 6570656177034.
It is an arithmetic number, because the mean of its divisors is an integer number (6570656177034).
Almost surely, 213141312354067 is an apocalyptic number.
13141312354067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141312354067 is an equidigital number, since it uses as much as digits as its factorization.
13141312354067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 41.
Adding to 13141312354067 its reverse (76045321314131), we get a palindrome (89186633668198).
The spelling of 13141312354067 in words is "thirteen trillion, one hundred forty-one billion, three hundred twelve million, three hundred fifty-four thousand, sixty-seven".
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