131413414204042 has 4 divisors (see below), whose sum is σ = 197120121306066. Its totient is φ = 65706707102020.

The previous prime is 131413414204031. The next prime is 131413414204043. The reversal of 131413414204042 is 240402414314131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 125522692023481 + 5890722180561 = 11203691^2 + 2427081^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131413414203989 and 131413414204007.

It is not an unprimeable number, because it can be changed into a prime (131413414204043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32853353551009 + ... + 32853353551012.

Almost surely, 2^{131413414204042} is an apocalyptic number.

131413414204042 is a deficient number, since it is larger than the sum of its proper divisors (65706707102024).

131413414204042 is an equidigital number, since it uses as much as digits as its factorization.

131413414204042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65706707102023.

The product of its (nonzero) digits is 36864, while the sum is 34.

Adding to 131413414204042 its reverse (240402414314131), we get a palindrome (371815828518173).

The spelling of 131413414204042 in words is "one hundred thirty-one trillion, four hundred thirteen billion, four hundred fourteen million, two hundred four thousand, forty-two".