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131413535143 = 1111946685013
BaseRepresentation
bin111101001100011011…
…0110110100110100111
3110120012102202021022021
41322120312312212213
54123113331111033
6140212012044011
712331356422032
oct1723066664647
9416172667267
10131413535143
1150806572aa0
1221576163607
13c5139b1c67
146509102019
153641ecdb2d
hex1e98db69a7

131413535143 has 4 divisors (see below), whose sum is σ = 143360220168. Its totient is φ = 119466850120.

The previous prime is 131413535129. The next prime is 131413535147. The reversal of 131413535143 is 341535314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131413535143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131413535099 and 131413535108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131413535147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5973342496 + ... + 5973342517.

It is an arithmetic number, because the mean of its divisors is an integer number (35840055042).

Almost surely, 2131413535143 is an apocalyptic number.

131413535143 is a deficient number, since it is larger than the sum of its proper divisors (11946685025).

131413535143 is a wasteful number, since it uses less digits than its factorization.

131413535143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11946685024.

The product of its digits is 32400, while the sum is 34.

Adding to 131413535143 its reverse (341535314131), we get a palindrome (472948849274).

The spelling of 131413535143 in words is "one hundred thirty-one billion, four hundred thirteen million, five hundred thirty-five thousand, one hundred forty-three".

Divisors: 1 11 11946685013 131413535143