Base | Representation |
---|---|
bin | 11101111000010100111011… |
… | …111101011010100111001010 |
3 | 122020022001210222212012211010 |
4 | 131320110323331122213022 |
5 | 114211042104244424432 |
6 | 1143254451411544350 |
7 | 36452233260055626 |
oct | 3570247375324712 |
9 | 566261728765733 |
10 | 131414120311242 |
11 | 38966462a5832a |
12 | 128a4b2abbb0b6 |
13 | 58433b56a36c2 |
14 | 2464697c3c186 |
15 | 102d5b21a43cc |
hex | 77853bf5a9ca |
131414120311242 has 16 divisors (see below), whose sum is σ = 262995540603552. Its totient is φ = 43776823440240.
The previous prime is 131414120311231. The next prime is 131414120311291. The reversal of 131414120311242 is 242113021414131.
It is a super-3 number, since 3×1314141203112423 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6970822333 + ... + 6970841184.
It is an arithmetic number, because the mean of its divisors is an integer number (16437221287722).
Almost surely, 2131414120311242 is an apocalyptic number.
131414120311242 is an abundant number, since it is smaller than the sum of its proper divisors (131581420292310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131414120311242 is a wasteful number, since it uses less digits than its factorization.
131414120311242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13941665093.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 131414120311242 its reverse (242113021414131), we get a palindrome (373527141725373).
The spelling of 131414120311242 in words is "one hundred thirty-one trillion, four hundred fourteen billion, one hundred twenty million, three hundred eleven thousand, two hundred forty-two".
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