Base | Representation |
---|---|
bin | 10011000111111001000… |
… | …010001011011001011010 |
3 | 11122122000220010112200210 |
4 | 103013321002023121122 |
5 | 133012331114414114 |
6 | 2443413051511550 |
7 | 163641456145260 |
oct | 23077102133132 |
9 | 4578026115623 |
10 | 1314143123034 |
11 | 467363595925 |
12 | 192833a585b6 |
13 | 96c00267cb1 |
14 | 47867a7a430 |
15 | 242b58ca259 |
hex | 131f908b65a |
1314143123034 has 16 divisors (see below), whose sum is σ = 3003755709888. Its totient is φ = 375469463712.
The previous prime is 1314143123023. The next prime is 1314143123071. The reversal of 1314143123034 is 4303213414131.
It is a super-2 number, since 2×13141431230342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1314143122992 and 1314143123010.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15644560947 + ... + 15644561030.
It is an arithmetic number, because the mean of its divisors is an integer number (187734731868).
Almost surely, 21314143123034 is an apocalyptic number.
1314143123034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1314143123034 is an abundant number, since it is smaller than the sum of its proper divisors (1689612586854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314143123034 is a wasteful number, since it uses less digits than its factorization.
1314143123034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31289121989.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 1314143123034 its reverse (4303213414131), we get a palindrome (5617356537165).
The spelling of 1314143123034 in words is "one trillion, three hundred fourteen billion, one hundred forty-three million, one hundred twenty-three thousand, thirty-four".
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