13142024412021 has 48 divisors (see below), whose sum is σ = 19484252751600. Its totient is φ = 8530821411840.

The previous prime is 13142024411969. The next prime is 13142024412073. The reversal of 13142024412021 is 12021442024131.

13142024412021 is a `hidden beast` number, since 1 + 3 + 14 + 2 + 0 + 2 + 441 + 202 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (13142024411969) and next prime (13142024412073).

It can be written as a sum of positive squares in 8 ways, for example, as 340577288100 + 12801447123921 = 583590^2 + 3577911^2 .

It is not a de Polignac number, because 13142024412021 - 2³⁸ = 12867146505077 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142024412221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 614188695 + ... + 614210091.

It is an arithmetic number, because the mean of its divisors is an integer number (405921932325).

Almost surely, 2^{13142024412021} is an apocalyptic number.

It is an amenable number.

13142024412021 is a deficient number, since it is larger than the sum of its proper divisors (6342228339579).

13142024412021 is a wasteful number, since it uses less digits than its factorization.

13142024412021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24646 (or 24643 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 13142024412021 its reverse (12021442024131), we get a palindrome (25163466436152).

The spelling of 13142024412021 in words is "thirteen trillion, one hundred forty-two billion, twenty-four million, four hundred twelve thousand, twenty-one".